39 ml of a gas is at 0 celsius. What is the new temperature if the volume is decreased to 35 ml?

To determine the new temperature when the volume of the gas is decreased, we can use Charles's Law. Charles's Law states that for a given amount of gas at constant pressure, the volume of the gas is directly proportional to its temperature in Kelvin.

To solve this problem, we can use the equation:

(V1 / T1) = (V2 / T2)

Where:
V1 is the initial volume (39 ml)
T1 is the initial temperature (0 °C = 273 K)
V2 is the final volume (35 ml)
T2 is the final temperature (unknown)

Rearranging the equation to solve for T2:

T2 = (V2 * T1) / V1

Plugging in the given values:

T2 = (35 ml * 273 K) / 39 ml

Simplifying:

T2 = 2415 K / 39 ml

T2 = 61.92 K

Converting back to Celsius:

T2 = 61.92 K - 273

T2 ≈ -211.08 °C

Therefore, the new temperature is approximately -211.08 °C when the volume is decreased to 35 ml.