Please let me know if my equation is correct,taken from the following word problem.

If you react Iron(111)oxide with carbon monoxide,you will produce liquid iron and carbon dioxide.

Fe2O3 + CO --> Fe + CO2.

If I'm correct..how do I balance this.

Thanks for your help.

Fe2O3 + 3CO --> 2Fe + 3CO2.

I remind you that in iron(III) oxide, the III are capital "eyes" and not "ones".

Yes, your equation is correct. To balance the equation, you need to make sure that the number of atoms of each element on both sides of the equation is the same.

Here's how you can balance the equation step by step:

1. Start by counting the number of atoms on each side of the equation:

Left side (reactants):
Fe: 2
O: 3
C: 1

Right side (products):
Fe: 1
O: 2
C: 1

2. Balance the elements that appear in the largest number first. In this case, there are 3 oxygen (O) atoms on the left side and 2 oxygen atoms on the right side. To balance the oxygen, add a coefficient of 3 in front of CO2:

Fe2O3 + CO --> Fe + 3CO2

3. Now, let's balance the iron (Fe) atoms. There are 2 iron atoms on the left side and only 1 on the right side. To balance this, add a coefficient of 2 in front of Fe:

2Fe2O3 + CO --> 2Fe + 3CO2

4. Finally, let's check the carbon (C) atoms. There is already one carbon atom on each side, so carbon is already balanced.

Now, the equation is balanced:

2Fe2O3 + CO --> 2Fe + 3CO2

This balanced equation shows that when you react 2 moles of Fe2O3 with 1 mole of CO, you will produce 2 moles of Fe and 3 moles of CO2.