What is the concentration of 10g of NaOH dizzolved in 0.95 L of water?
moles NaOH = grams/molar mass
M = moles/L
Should the answer be in molarity, then?
The question doesn't specify the unit; I assume molarity was the unit desired. Density is not given; therefore, one couldn't obtain molality.
Covert g to mols then divide by L to obtain M=molarity
To calculate the concentration of a solution, you need to know the amount of solute (in this case, NaOH) and the volume of the solution.
In this case, you have 10 grams of NaOH dissolved in 0.95 liters of water.
The next step is to convert the mass of NaOH to moles. To do this, you need the molar mass of NaOH, which is 22.99 g/mol (atomic mass of Na) + 16.00 g/mol (atomic mass of O) + 1.01 g/mol (atomic mass of H) = 39.99 g/mol.
Now, you can calculate the number of moles of NaOH:
moles = mass / molar mass
moles = 10 g / 39.99 g/mol ≈ 0.250 moles
Finally, you can calculate the concentration (C) using the formula:
C = moles / volume
C = 0.250 moles / 0.95 L ≈ 0.263 M
Therefore, the concentration of the NaOH solution is approximately 0.263 M.