# chem/math

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I need to fid the activation energy but i forgot how to solve for Ea

4.58*10^-15=e^(Ea/2537.02)

can you show the work thank you

• chem/math -

take the ln of both sides:
ln [4.58*10^-15] = ln [e^(Ea/2537.02)]
*since ln has a base of e, the term at the right side becomes:
ln [4.58*10^-15] = (Ea/2537.02)

now you solve for Ea. :)

• chem/math -

thanks that helps alot

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