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Q. A force F = (3.99xi + 2.86yj) N acts on an object as it moves in the x direction from the origin to x = 4.45 m. Calculate the work done on the object by the force.

Attemp:
since we only consider x direction i multiplied 3.99 by 4.45 but it didn't work out.

  • college Physics -

    work done is integral Fdotdx

    INT (3.99x)dx= 1/2 3.99x^2 over limits, or

    work= 1/2 3.99 (4.45)^2

    I am assuming you are taking calculus.

  • college Physics -

    Thank You!!!

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