math
posted by jenna .
(Y+3)^2/5+4(Y+3)^7/5=0
solve this equation by factoring. I don't know how to factor problems like this

Remember to take out a common factor with the lowest exponent
(Y+3)^2/5+4(Y+3)^7/5=0
(y+3)^2/5 [ 1 + 4(y+3) ] = 0
(y+3)^2.5 (4y + 13) = 0
(y+3)^2/5 = 0
y+3 = 0
y = 3
or
4y+13=0
y = 13/4