# College Algebra

posted by .

find th quadratic fuction that has a vertix of (8.-3) and whose graph goest throught the point (-6, -395)

• College Algebra -

V(8 , -3) , P(-6 , -395).

Y = a(x - h)^2 + K.
-395 = a(-6 - 8)^2 + (-3),
-395 = 196a - 3,
196a = -395 + 3,
196a = -392,
a = -392 / 196 = -2.

Eq: y = -2(x - 8)^2 - 3(Vertex form).

This parabola opens downward, because a < 0.

## Similar Questions

Please explain to me how to do the following problems, I don't understand them. Thanks! Find the x-intercepts (if any) for the graph of the quadratic function. 1.f(x) = (x + 2)2 - 4 Find the y-intercept for the graph of the quadratic …
2. ### Pre-calc

1. Find the equation for a quadratic function whose vertex is (2,5) and whose graph contains the point (-8,15). 2.What are the x- and y- intercepts for y=2x^2+x-6 Plesee explai. I want to learn to learn how to do them.
3. ### College Algebra

find th quadratic fuction that has a vertix of (8.-3) and whose graph goest throught the point (-6, -395)
4. ### Algebra

Find the equation of the quadratic function f whose graph is shown below. Ponts on the graph are (-3,-1)(-2,-4) f(x)=
5. ### Algebra

Find a power function of the form y=ax^b whose graph passes throught the points (2, 5) and (8, 12). How do i solve this?
6. ### college algebra

determine the quadratic function f whose graph is given. the vertex is (1,-3) y intercept is -2 please show work so i can see how this is done, thank you!
7. ### college algebra

determine the quadratic function of f whose graph is the vertex of (1,-4) and the y-intercept is -3.
8. ### MATH

Find two quadratic functions whose graph have given x-intercepts. Find one function whose graph opens upward and another whose graph opens downward. (-4,0) (0,0)
9. ### Math

Find two quadratic functions whose graph have the given x-intercepts. Find one function whose graph opens upward and another whose graph open downdward. (-5/2,0),(-2,0)
10. ### College Algebra

The graph of a quadratic function f(x) is shown above. It has a vertex at (-2,4) and passes the point (0,2). Find the quadratic function y=a(x-(-2))^2+4 y=a(x+2)+4 2=a(x+2)+4 -4 -4 -2=a(0+2)/2 -1+ a function -1(x+2)+4 ?

More Similar Questions