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College Algebra

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find th quadratic fuction that has a vertix of (8.-3) and whose graph goest throught the point (-6, -395)

  • College Algebra -

    V(8 , -3) , P(-6 , -395).

    Y = a(x - h)^2 + K.
    -395 = a(-6 - 8)^2 + (-3),
    -395 = 196a - 3,
    196a = -395 + 3,
    196a = -392,
    a = -392 / 196 = -2.

    Eq: y = -2(x - 8)^2 - 3(Vertex form).

    This parabola opens downward, because a < 0.

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