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In a tennis serve, a .074 kg ball can be accelerated from rest to 40 m/s over a distance of 0.79 m.Find the magnitude of the average force exerted by the racket on the ball during the serve.

  • physics -

    V ^2= 2ad =(40)^2,
    2 * a * 0.79 = 1600,
    1.58a = 1600,
    a = 1600 / 1.58 = 1012.7 m/s^2.

    F = ma = 0.74kg*1012.7 m/s^2 = 749.4N.

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