multiply:
(2x^4y^2)^3 (4x^2y)^2
Is this right?
128x^11y^8
Not sure.
Did some rethinking..is it
128x^16y^8
?
I got 128x^16y^8
Great...i was adding the exponents that were on the outside instead of multiplying it.
Took me a while to remember the rule. Thanks Ron.
To multiply the given expression, we need to use the properties of exponents.
Let's break it down step by step:
First, let's simplify the expression inside the parentheses: (2x^4y^2)^3
To raise a power to another power, we multiply the exponents. So, (2x^4y^2)^3 becomes 2^3 * (x^4)^3 * (y^2)^3.
2^3 = 8 (since 2^3 = 2 * 2 * 2)
(x^4)^3 = x^(4*3) = x^12
(y^2)^3 = y^(2*3) = y^6
Therefore, (2x^4y^2)^3 simplifies to 8x^12y^6.
Next, let's simplify the expression outside the parentheses: (4x^2y)^2
To raise a power to another power, we multiply the exponents. So, (4x^2y)^2 becomes 4^2 * (x^2)^2 * y^2.
4^2 = 16 (since 4^2 = 4 * 4)
(x^2)^2 = x^(2*2) = x^4
y^2 remains the same.
Therefore, (4x^2y)^2 simplifies to 16x^4y^2.
Now, we can multiply the simplified expressions: 8x^12y^6 * 16x^4y^2.
To multiply, we multiply the coefficients (8 * 16 = 128) and add the exponents with the same base (x^12 * x^4 = x^(12+4) = x^16, and y^6 * y^2 = y^(6+2) = y^8).
Therefore, our final answer is 128x^16y^8.
So, the correct answer is 128x^16y^8, not 128x^11y^8.