I need the molecular, ionic and net ionic equations for Potassium carbonate and hydroiodic acid........i'm clueless please help as much as you can!
K2CO3 + HI >> KI + H20 + CO2 and you have to balance it. Carbonates and acids yield carbon dioxide, water, and a salt
2K+ + CO3-- + H+ + I->>K+ + I- + H2O + CO2 and balance it.
Net ionic: H2O and CO2 are formed,
H+CO3-- > H2O + CO2 and balance it.
Well, alright! Let's dive into the wonderful world of chemistry equations for the reaction between potassium carbonate (K2CO3) and hydroiodic acid (HI).
First, let's look at the molecular equation, which shows the reactants and products in their complete, balanced form:
K2CO3 + 2HI -> 2KI + H2CO3
Next, we can break down the ionic equation by separating the reactants and products into their respective ions:
2K+ + CO3²- + 2H+ + 2I- -> 2K+ + 2I- + H2CO3
Now, let's simplify this equation further to the net ionic equation by removing any spectator ions that don't actively participate in the reaction. In this case, the potassium ions (K+) and iodide ions (I-) are spectators:
CO3²- + 2H+ -> H2CO3
And there you have it! The molecular equation is K2CO3 + 2HI -> 2KI + H2CO3, the ionic equation is 2K+ + CO3²- + 2H+ + 2I- -> 2K+ + 2I- + H2CO3, and the net ionic equation is CO3²- + 2H+ -> H2CO3.
Sure! I can help you with that. Let's start by writing the molecular equation for the reaction between potassium carbonate (K2CO3) and hydroiodic acid (HI).
The chemical formula for potassium carbonate is K2CO3, and the chemical formula for hydroiodic acid is HI.
The balanced molecular equation is:
K2CO3 + 2HI -> 2KI + H2O + CO2
Next, let's write the ionic equation. This equation shows the dissociated ions in the reaction.
The ionic equation is:
2K+ + CO32- + 2H+ + 2I- -> 2K+ + 2I- + H2O + CO2
Finally, let's write the net ionic equation. This equation only includes the species that are directly involved in the chemical reaction.
The net ionic equation is:
CO32- + 2H+ -> H2O + CO2
In the net ionic equation, the potassium ions (K+) and iodide ions (I-) are spectator ions. They do not participate directly in the reaction and therefore are not included.
I hope this helps! If you have any more questions, feel free to ask.
Sure! I can help you with that. Let's break down the process step by step to determine the molecular, ionic, and net ionic equations.
Step 1: Write the Chemical Formulas
First, we need to write the chemical formulas for Potassium carbonate and hydroiodic acid. The chemical formula for Potassium carbonate is K2CO3, and for hydroiodic acid, it is HI.
Step 2: Determine the Ionic Equation
To write the ionic equation, we need to split the reactants into their respective ions. Potassium carbonate dissociates into two potassium ions (K+) and one carbonate ion (CO3 2-). Hydroiodic acid dissociates into one hydrogen ion (H+) and one iodide ion (I-).
K2CO3 (s) → 2K+ (aq) + CO3 2- (aq)
HI (aq) → H+ (aq) + I- (aq)
Step 3: Determine the Molecular Equation
The molecular equation represents the reaction without considering the dissociation of the compounds. It shows the formulas of the reactants and products in their molecular form.
K2CO3 (s) + 2HI (aq) → 2KI (aq) + H2CO3 (aq)
Step 4: Determine the Net Ionic Equation
The net ionic equation only includes the species that undergo a chemical change during the reaction, excluding the spectator ions. Spectator ions are the ions that appear on both sides of the equation and do not participate in the reaction.
To determine the net ionic equation, we first need to identify the spectator ions. The spectator ions in this case are the potassium ions (K+). They appear on both sides of the equation and do not undergo any chemical change. Therefore, we can exclude them from the net ionic equation.
Net ionic equation:
CO3 2- (aq) + 2H+ (aq) → H2CO3 (aq)
So, the molecular equation is K2CO3 (s) + 2HI (aq) → 2KI (aq) + H2CO3 (aq), and the net ionic equation is CO3 2- (aq) + 2H+ (aq) → H2CO3 (aq).