Economics International Economics Exchange Rates and Stabilization
Why was US participation in the international economic system vital?
for exchange-rate stabilization.
Could someone explain this to me. I've already gone through websites.
this was during FDR's presidency
answered by
Amy
13 years ago
0
0
We needed to trade goods with the world. This was most efficient when we knew from one month to the next what the dollar was worth compared with other currencies.
answered by
Ms. Sue
13 years ago
0
0
but when the US withdrew from exchange-rate stabilization, how was this a bad thing for other countries?
answered by
Amy
13 years ago
0
0
The exchange rate also determined the profit made from goods bought from and sold to other countries.
answered by
Ms. Sue
13 years ago
0
0
like mainly the US
answered by
Amy
13 years ago
0
0
You can ask a new question or answer this question .
Similar Questions
Top answer:
Could someone tell me why FDR wanted inflation? - because of the economic slump ?
Read more.
Top answer:
During the Great Depression, international relations faced several challenges, including issues with
Read more.
Top answer:
In the circular flow of income model, economic activity is depicted as a flow of goods, services,
Read more.
Top answer:
stabilization can actually increase, rather than decrease, the magnitudes of economic fluctuations.
Read more.
Top answer:
A fixed exchange rate system is a monetary system in which a country's currency is pegged to the
Read more.
Top answer:
When FDR decided not to take part in helping the global depression, it had significant consequences
Read more.
Top answer:
http://www.investopedia.com/terms/b/bot.asp
Read more.
Top answer:
In the 1920s, the French Government aimed to increase its gold reserves by manipulating its exchange
Read more.
Couple questions here... "Under fixed exchange rates," A. The Free Market is the major determinant of the exchange rate. B.
Top answer:
To answer these questions, let's break down the options and see which one is correct for each
Read more.