Post a New Question


posted by .

so im done with everything except fro this question : A(n) 2.3 kg object moving with a speed of 8.6 m/s collides with a(n) 4 kg object moving with a velocity of 8.8 m/s in a direction39.0135◦ from the initial direction of motion mof the 2.3 kg object.What is the speed of the two objects afterthe collision if they remain stuck together?
Answer in units of m/s.


    Find initial momentum for the smaller object, via p1 = mv. Think of this momentum as being in the x-direction. Now break up the other objects momentum into its x and y components, p2x = mvcos(theta) and p2y = mvsin(theta). Final momentum in x-direction = p1+p2x and final momentum in y-direction = p2y. Use these components to find the momentum in the actual direction of the motion. Divide this momentum by the combined mass of the objects in order to find v. In order to find the change in direction, take the inverse tan of (p2y)/(p1+p2x). This is for the AP Physics students of decades to come.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question