The centers of a 13 kg lead ball and a 130 g lead ball are separated by 5.0 cm.
What gravitational force does each exert on the other?
F=G13*.130/.05^2
.07535
To calculate the gravitational force between two objects, we can use the formula:
F = G * ((m1 * m2) / r^2)
where:
F is the gravitational force,
G is the gravitational constant (6.674 × 10^-11 N m^2 / kg^2),
m1 and m2 are the masses of the objects, and
r is the distance between the centers of the objects.
Let's calculate the gravitational force for each ball:
For the 13 kg lead ball:
m1 = 13 kg
m2 = 130 g = 0.13 kg
r = 5.0 cm = 0.05 m
Plugging in the values into the formula, we get:
F1 = (6.674 × 10^-11 N m^2 / kg^2) * [(13 kg * 0.13 kg) / (0.05 m)^2]
Simplifying the expression:
F1 = (6.674 × 10^-11 N m^2 / kg^2) * (1.69 kg^2 / 0.0025 m^2)
Calculating the value, we find:
F1 ≈ 7.71984 × 10^-6 N
So, the gravitational force exerted by the 13 kg lead ball on the other ball is approximately 7.71984 × 10^-6 N.
For the 130 g lead ball:
m1 = 0.13 kg
m2 = 13 kg
r = 5.0 cm = 0.05 m
Plugging in the values into the formula, we get:
F2 = (6.674 × 10^-11 N m^2 / kg^2) * [(0.13 kg * 13 kg) / (0.05 m)^2]
Simplifying the expression:
F2 = (6.674 × 10^-11 N m^2 / kg^2) * (1.69 kg^2 / 0.0025 m^2)
Calculating the value, we find:
F2 ≈ 7.71984 × 10^-6 N
So, the gravitational force exerted by the 130 g lead ball on the other ball is also approximately 7.71984 × 10^-6 N.
Therefore, both balls exert the same gravitational force of approximately 7.71984 × 10^-6 N on each other.
To calculate the gravitational force between two objects, we can use Newton's law of universal gravitation, which states that the gravitational force (F) between two objects is given by the equation:
F = (G * m1 * m2) / r^2
Where:
- F is the gravitational force
- G is the gravitational constant (approximately 6.67430 × 10^-11 N m^2/kg^2)
- m1 and m2 are the masses of the objects
- r is the distance between the centers of the objects
In this case, we have a 13 kg lead ball (m1) and a 130 g lead ball (m2), which is equivalent to 0.13 kg. The distance between their centers (r) is given as 5.0 cm, which is equivalent to 0.05 m.
Let's calculate the gravitational force between the two lead balls:
For the first lead ball (13 kg):
F1 = (G * m1 * m2) / r^2
= (6.67430 × 10^-11 N m^2/kg^2 * 13 kg * 0.13 kg) / (0.05 m)^2
For the second lead ball (0.13 kg):
F2 = (G * m1 * m2) / r^2
= (6.67430 × 10^-11 N m^2/kg^2 * 0.13 kg * 13 kg) / (0.05 m)^2
Calculating these values will give you the gravitational force exerted by each lead ball on the other.