x(x-3)+4= 3x^2 - 2(x+8)
Divided by 3
To solve this equation, you need to follow these steps:
Step 1: Distribute and combine like terms on both sides of the equation:
x(x-3) + 4 = 3x^2 - 2(x+8)
Expanding the left side:
x^2 - 3x + 4 = 3x^2 - 2x - 16
Step 2: Simplify the equation by combining like terms:
x^2 - 3x + 4 = 3x^2 - 2x - 16
Rearranging the terms:
0 = 3x^2 - 2x - x^2 + 3x - 16 - 4
Combining like terms:
0 = 2x^2 + x - 20
Step 3: Divide the whole equation by 3 to isolate the quadratic term.
(2x^2 + x - 20) / 3 = 0
Dividing each term inside the parentheses by 3:
(2/3)x^2 + (1/3)x - (20/3) = 0
So, the divided equation is (2/3)x^2 + (1/3)x - (20/3) = 0.