35.00 grams of propane C3H8 are burned. How many grams of CO2 ARE PRODUCED
Here is an example stoichiometry problem I've posted. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine how many grams of CO2 are produced when 35.00 grams of propane (C3H8) are burned, we need to calculate the stoichiometric ratio between propane and carbon dioxide (CO2). The balanced equation for the combustion of propane is as follows:
C3H8 + 5O2 -> 3CO2 + 4H2O
From this equation, we can see that one mole of propane (C3H8) produces three moles of carbon dioxide (CO2). We will use this stoichiometric ratio to calculate the answer.
Step 1: Calculate the molar mass of propane (C3H8):
- Carbon (C) has a molar mass of 12.01 g/mol.
- Hydrogen (H) has a molar mass of 1.01 g/mol.
Therefore, the molar mass of propane (C3H8) is:
(3 × 12.01 g/mol) + (8 × 1.01 g/mol) = 44.1 g/mol
Step 2: Calculate the number of moles of propane (C3H8) in 35.00 grams:
Number of moles = mass / molar mass
Number of moles = 35.00 g / 44.1 g/mol ≈ 0.793 mol
Step 3: Use the stoichiometric ratio between propane (C3H8) and carbon dioxide (CO2):
1 mol of propane produces 3 moles of carbon dioxide.
Therefore, for 0.793 mol of propane, the number of moles of carbon dioxide produced is:
0.793 mol × 3 mol CO2 / 1 mol C3H8 = 2.38 mol CO2
Step 4: Calculate the mass of carbon dioxide produced using its molar mass:
- Carbon (C) has a molar mass of 12.01 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
Therefore, the molar mass of carbon dioxide (CO2) is:
12.01 g/mol + (2 × 16.00 g/mol) = 44.01 g/mol
Mass of carbon dioxide = number of moles × molar mass
Mass of carbon dioxide = 2.38 mol × 44.01 g/mol ≈ 104.79 g
Therefore, approximately 104.79 grams of carbon dioxide (CO2) are produced when 35.00 grams of propane (C3H8) are burned.
To determine the grams of CO2 produced when 35.00 grams of propane (C3H8) are burned, you need to use the balanced chemical equation and molar masses.
The balanced chemical equation for the combustion of propane is:
C3H8 + 5O2 → 3CO2 + 4H2O
From the equation, you can see that for every 1 mole of propane burned, 3 moles of CO2 are produced.
To find the moles of propane, divide the given mass (35.00 grams) by the molar mass of propane (C3H8).
The molar mass of C3H8 is calculated as:
(3 × 12.01 g/mol) + (8 × 1.01 g/mol) = 44.11 g/mol
So, the moles of propane = 35.00 g / 44.11 g/mol
Next, using the mole ratio from the balanced equation, you can calculate the moles of CO2 produced. From the equation, you can see that 3 moles of CO2 are produced for every 1 mole of propane burned.
Therefore, the moles of CO2 produced = moles of propane × (3 moles CO2 / 1 mole C3H8)
Finally, to determine the grams of CO2 produced, multiply the moles of CO2 produced by the molar mass of CO2.
The molar mass of CO2 is calculated as:
(1 × 12.01 g/mol) + (2 × 16.00 g/mol) = 44.01 g/mol
So, the grams of CO2 produced = moles of CO2 × 44.01 g/mol
Calculate the moles of propane:
moles of propane = 35.00 g / 44.11 g/mol
Calculate the moles of CO2 produced:
moles of CO2 = moles of propane × (3 moles CO2 / 1 mole C3H8)
Calculate the grams of CO2 produced:
grams of CO2 = moles of CO2 × 44.01 g/mol
Performing the calculations will give you the answer.