I'm in 8th grade, im in algebra, and this is my question:
x=a+b+c
-----
ab solve for a.
please help!!
..what i did not understand is this one: "ab solve for a", or are you trying to say solve for 'a' in the given equation? if it is:
to solve for 'a', transpose all terms to the other side such that 'a' will be left on one side of the equation,, in this case we transpose 'b' and 'c' on the left side but to do that you must reverse their signs (positive becomes negative):
x = a + b + c
x - b - c = a , or we can rewrite this as
a = x - b - c
so there,, i hope this helps :)
9a-1+8c-8a+c
To solve for "a" in the equation x = (a+b+c)/(ab), we need to isolate "a" on one side of the equation.
Step 1: Multiply both sides of the equation by ab to eliminate the denominator.
xab = a+b+c
Step 2: Distribute the "x" on the left side of the equation.
xab = xa + xb + xc
Step 3: Move all terms involving "a" to one side of the equation.
xab - xa = xb + xc
Step 4: Factor out "a" on the left side of the equation.
a(xb - x) = xb + xc
Step 5: Divide both sides of the equation by (xb - x) to isolate "a".
a = (xb + xc)/(xb - x)
Therefore, the solution for "a" is a = (xb + xc)/(xb - x).