write an ionic and net ionic equation for the following reaction between Fe3+ and NH4OH.
Please check my answer!! Thank you.
My answer is:
ionic: Fe3+(aq) + NH4OH--> Fe(OH)3 + NH4+
net ionic: Fe3+ +OH- -->Fe(OH)3
Your ionic equation is correct. Since NH4OH is a weak electrolyte (actually it has been shown that NH4OH doesn't exist), I would write the same equation as the net ionic equation. Then if I really wanted to attract attention I would change it to write:
Fe^+3(aq) + NH3(g) + H2O(l) ==> Fe(OH)3(s) + NH4^+
Your answer is almost correct, but you need to consider the dissociation of ammonium hydroxide (NH4OH) in the net ionic equation. The correct ionic and net ionic equations are:
Ionic equation: Fe3+(aq) + 3NH4OH(aq) → Fe(OH)3(s) + 3NH4+(aq)
Net ionic equation: Fe3+(aq) + 3OH-(aq) → Fe(OH)3(s)
Your answer is close, but there are a couple of mistakes.
First, NH4OH should be written as NH3 + H2O since it dissociates in water. NH4+ is the ammonium ion and OH- is the hydroxide ion.
Second, Fe(OH)3 is the correct formula for the product.
So, the corrected ionic equation would be:
Fe3+(aq) + 3NH3 + 3H2O -> Fe(OH)3 + 3NH4+
To write the net ionic equation, you need to eliminate the spectator ions, which are the ions that appear on both sides of the equation unchanged. In this case, NH4+ and H2O are spectator ions.
The net ionic equation would be:
Fe3+(aq) + 3OH-(aq) -> Fe(OH)3(s)
I hope this helps!