From the top of a tall building, a gun is fired. The bullet leaves the gun at a speed of 340 m/s, parallel to the ground. As the drawing shows, the bullet puts a hole in a window of another building and hits the wall that faces the window. h is 0.50 m and d is 7.9 m. Assume that the bullet does not slow down as it passes through the window

and the question?

The question is

determine the height and the distance

24m

To find the time it takes for the bullet to travel from the gun to the window, we can use the equation:

time = distance / speed

In this case, the distance is the horizontal distance (d) between the buildings, and the speed is the initial speed of the bullet (340 m/s). Therefore, the time it takes for the bullet to reach the window is:

time = 7.9 m / 340 m/s = 0.02324 s

Next, to find the vertical distance that the bullet falls (h), we can use the equation:

vertical distance = (1/2) * acceleration * time^2

Since the only force acting on the bullet vertically is the force of gravity (acceleration due to gravity is approximately 9.8 m/s^2), we can substitute these values into the equation:

vertical distance = (1/2) * 9.8 m/s^2 * (0.02324 s)^2 = 0.00205 m

Therefore, the bullet falls a vertical distance of approximately 0.00205 meters.

Finally, to calculate the total distance from the top of the tall building to the wall that the bullet hits, we can use the Pythagorean theorem:

total distance = sqrt((horizontal distance)^2 + (vertical distance)^2)

total distance = sqrt((7.9 m)^2 + (0.00205 m)^2) = 7.9 m

Thus, the total distance from the top of the tall building to the wall that the bullet hits is approximately 7.9 meters.