# math

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3a2 - (3a - x + b)

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All you can do is distribute. 3a^2-3a+x-b

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Find the first five terms of the sequence for which a1=5,and an+1=3an+1. an+1=3an+1 a1+1=3a1+1 a2=3(5)+1 a2=16 a2+1=3a2+1 a3=3(16)+1 a3=49 a3+1=3a3+1 a4=3(49)+1 a4=148 a4+1=3a4+1 a5=3(148)+1 a5=445 so the first five terms are: 5,16,49,148,445

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