Physics
posted by Vivek .
A car reaches a speed of 40m/s from rest in a time of 8 seconds. After the 8 seconds, the car travels at a constant velocity fro 200meters when it runs out of gas. The car slowly comes to rest 30 seconds after running out of gas.
Calculate acceleration for the first 8 seconds

acceleration is change in velocity over time, or:
a = (v2  v1)/t
where v1 = 0, v2 = 40 m/s and t = 8 s
therefore:
a = (40  0)/8
a = 5 m/(s^2)
so there,, :) 
Thanks to jai for the correct answer. This is another question that contains a lot of irrelevant information for you to choose among. Whatever happens after 8 seconds does not affect the answer.