physics

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A boy standing on top of a hill throws a stone horizontally. The stone hits the ground at the foot of the hill 2.5 s later. How high is the hill ?

  • physics -

    The rock was thrown horizontally, so u, the initial vertical velocity = 0
    Use equations of motion:
    u = initial vertical velocity = 0
    S = vertical distance travelled, m
    t = time, s
    g = acceleration due to gravity, 9.81 m/s²

    S = ut + (1/2)at²
    Solve for S.

  • physics -

    v1y = 0
    a = -9.8 m/s
    t = 2.5s
    d = ?

    d = v1t + 1/2(a)(t)^2
    d = 0 + 1/2 (-9.8)(2.5)^2
    d = -30.625

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