I'm in 5th grade pls. help.
Amanda has a collection of X, Y and Z. Every X is a Y. One half the Z's are Y's. There are 3 times as many Y's as X's. Amanda has 50 Z's and 40 X's. No Z is an X. How many Y's does Amanda have that are neither X's nor Z's?
pls. help
yj537756
To solve this problem, let's break down the given information and find a way to determine the number of Y's that are neither X's nor Z's.
1. Amanda has 40 X's.
2. Every X is a Y, so we know that Amanda also has 40 Y's.
3. There are 3 times as many Y's as X's, which means Amanda has a total of (3 * 40) = 120 Y's.
4. Amanda has 50 Z's.
5. One half the Z's are Y's, so half of the 50 Z's are Y's, which totals to (1/2 * 50) = 25 Y's.
6. No Z is an X, which means none of the 50 Z's are included in the 40 X's.
7. Thus, the Y's that are neither X's nor Z's are the remaining Y's, which is (120 - 40 - 25) = 55 Y's.
Therefore, Amanda has 55 Y's that are neither X's nor Z's.