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posted by Anonymous .
given that the energy released per fissin of Uranium235 nucleus is 200Mev, calculate the number of fissions and amount of energy available if 50g of Uranium235 is completely fissioned

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drwls
50 g of U235 is 50/235 = 0.2128 moles.
Multiply that by Avogadro's number for the number of atoms.
200 MeV = 200*10^6 eV*1.602*10^19 J/eV
= 3.2*10^11 J
E = 0.2128 moles*6.02^10^23 atoms/mole*3.2*10^11 J/atom =
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