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Total ¨C/1 ...A volleyball is spiked so that it has an initial velocity of 18 m/s directed downward at an angle of 50¡ã below the horizontal. What is the horizontal component of the ball's velocity when the opposing player fields the ball?
Use the horizontal component of the initial velocity, namely 18 m/s * cos(50°).
To find the horizontal component of the ball's velocity, you need to first find the vertical component of the velocity, and then use trigonometry to calculate the horizontal component.
Step 1: Find the vertical component of the velocity.
The initial velocity in the vertical direction can be found by using the formula:
V_y = V_initial * sin(theta)
where V_y is the vertical component of the velocity, V_initial is the initial velocity of the ball, and theta is the angle of the velocity below the horizontal.
Given: V_initial = 18 m/s and theta = 50°
Plugging the values into the formula, we have:
V_y = 18 m/s * sin(50°)
Step 2: Calculate the horizontal component of the velocity.
The horizontal component of the velocity can be found by using the formula:
V_x = V_initial * cos(theta)
where V_x is the horizontal component of the velocity, V_initial is the initial velocity of the ball, and theta is the angle of the velocity below the horizontal.
Given: V_initial = 18 m/s and theta = 50°
Plugging the values into the formula, we have:
V_x = 18 m/s * cos(50°)
Step 3: Calculate the horizontal component of the velocity when the ball is fielded.
Since the question asks for the horizontal component when the ball is fielded, we can directly use the value calculated in Step 2:
V_x = 18 m/s * cos(50°)
Now, you can use a calculator to find the numerical value of V_x.