posted by Adolfo .
A 0.130 kg baseball, traveling 35.0 m/s, strikes the catcher's mitt, which recoils 11.0 cm in bringing the ball to rest. What was the average force (in newtons) applied by the ball to the mitt?
Work done against mitt equals initial kinetic energy
F*X = (1/2) M V^2
X is the recoil distance in meters.
Solve for the force F, in Newtons
I got the same answer, but are sure this is the equation? I tried to use it with a similar problem, .140 kg baseball, traveling 35 m/s which recoils the mitt 17 cm and I keep getting the wrong answer
Okay sorry I figured it out, I was dividing by the X value in cm not m, in which case would cause the answer for the above to be 723.86 N not 7.24.