Find a number whose square root is 24 more than 5 times the number.
How do I set up this problem?
Thank you for any help!
see
http://www.jiskha.com/display.cgi?id=1287864562
5n = √n + 24
Solve for n.
I goofed. Reiny is right.
To set up this problem, let's assume the number we are looking for is x. The problem states that the square root of some number is 24 more than 5 times that number. So, we can write the equation as:
√x = 5x + 24
To solve this equation, we need to isolate the variable x.