A daredevil leaves the end of a ramp with a speed of 32.0 m/s if his speed is 29.8 m/s when he reaches the peak of the path, what is the maximum height that he reaches?
how do i do thiss?
well,his horzontal speed is all he has at the peak, so vertical speed at launch is
vi^2=32^2-29.8^2
solve for Vi
Then for height,
Vi^2=2*g*h solve for height