Suppose that the coefficient of kinetic friction of the rubber of a car tire and the street is Uk = 0.8. What is the deceleration of the car on a flat street if the driver brakes sharply, so all the wheels are locked and skidding?
F=ma
a=F/m
=μk*mg/m
=μk*g
=0.8*9.8 m/s²
= ...
To find the deceleration of the car when the wheels are locked and skidding, we can use the equation:
Deceleration = Coefficient of kinetic friction × Acceleration due to gravity
First, let's determine the acceleration due to gravity. The standard value for acceleration due to gravity is approximately 9.8 meters per second squared (m/s^2).
Next, we multiply the coefficient of kinetic friction (Uk) by the acceleration due to gravity. In this case, the coefficient of kinetic friction is given as 0.8.
Deceleration = 0.8 * 9.8 m/s^2 = 7.84 m/s^2
Therefore, the deceleration of the car on a flat street when the driver brakes sharply and the wheels are locked and skidding is approximately 7.84 m/s^2.