# Algebra II

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Jack usually mows his lawn in 6 hours. Marilyn can mow the same lawn in 7 hours. How long would it take if they were both working together?

• Algebra II -

Jack's rate = lawn/6
Marilyn's rate = lawn/7
combined rate = lawn/6 + lawn/7 = 13lawn/42

combined time = lawn/(13lawn/42) = 42/13 or 3.23 hours

it would take about 2 hours and 14 minutes.

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