Chemistry
posted by Nevaeh .
A 30.5 g sample of an alloy at 94.0°C is placed into 48.7 g water at 20.3°C in an insulated coffee cup. The heat capacity of the coffee cup (without the water) is 9.2 J/K. If the final temperature of the system is 31.1°C, what is the specific heat capacity of the alloy? (c of water is 4.184 J/g×K)

Chemistry 
DrBob222
[mass alloy x specific heat alloy x (TfinalTinitial)] + [(calorimeter constant x (TfinalTinitial)] = 0

Chemistry 
Nevaeh
(30.5)(X)(10.8)+(?)(10.8)=0
What number goes in the calorimeter constant ? 
Chemistry 
DrBob222
9.2 J/K = heat capacity of the coffee cup.

Chemistry 
Nevaeh
It's still not giving me the right answer. I'm pulling in the numbers, and doing the equation right. But, it keeps telling me, I am wrong.

Chemistry 
DrBob222
I didn't include the water and should have done so.
(mass water x specific heat water x (TfinalTinitial)) + (mass alloy x specific heat alloy x (TfinalTinitial)) + Ccal(TfinalTinitial) = 0 
Chemistry 
uchenna
so, what is the t final t initial for ccal?
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