posted by Ellen .
80.0 mL of water is initially at room temperature (22degrees C). A chilled steel rod at 2 degrees C is placed in the water. If the final temperature of the system is 21.2 degrees C, what is the mass of the steel bar?
Specific heat of water = 4.18J/g(degreesC)
Specific heat of steel = 0.452J/g(degrees C)
The specific heat of water is 4.18 J/g(degrees C). Calculate the molar heat capacity of water.