whats the x-intercepts of the graph
y = 42x2 + 28x
x-intercept: where y is equal to zero.
therefore:
0 = 42x^2 + 28x
0 = x(42x + 28)
x = 0 ; and
x = -28/42 = -2/3
x-int: (0,0) and (-2/3,0)
so there,, :)
X-intercept=-7&0
Y-intercept=0
To find the x-intercepts of the graph of a function, we need to set the value of y to zero and solve the equation for x. In this case, we have the equation y = 42x^2 + 28x.
1. Set y = 0: Start by setting the equation equal to zero: 0 = 42x^2 + 28x.
2. Factor out common terms: We can factor out a common factor of 14x from both terms: 0 = 14x(3x + 2).
3. Apply the zero product property: The zero product property states that if a product of factors equals zero, then at least one of the factors must be zero. Set each factor equal to zero and solve for x:
a. Set 14x = 0 and solve for x: x = 0.
b. Set 3x + 2 = 0 and solve for x: 3x = -2 --> x = -2/3.
Therefore, the x-intercepts of the graph are x = 0 and x = -2/3.