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how do you write an equation of the line containing point (4,-3) and perpendicular to the line y=3x-5? show steps please

  • math -

    you should have come across the property that the slopes of perpendicular lines are "negative reciprocals" of each other.

    slope of y = 3x+ 5 is 3
    so the slope of new line is -1/3

    new equation: y = (-1/3)x + b
    sub in the point(4,-3) to find b
    replace b in the new equation and you are done.

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