Find the x and y intercepts:
3x - 2y = -12
i know the anwser is (2 , -3) but how do i show the work that i found that anwser?
for the x intercept, put y=0 in the equation,solve for x. For the y intercept,do the reverse.
eh idk. i hate showing work so im just not going to do. i hate math i suck at it. im more biology, chemistry, science kid.^^
To find the x and y intercepts of a linear equation, you need to determine the points at which the line intersects the x-axis and the y-axis.
To find the x-intercept, we set y to zero and solve the equation. So, let's replace y with 0 in the given equation:
3x - 2(0) = -12
Simplifying, we get:
3x = -12
Now, isolate x by dividing both sides of the equation by 3:
x = -12/3
Simplifying further, we get:
x = -4
Therefore, the x-intercept is -4.
To find the y-intercept, you need to set x to zero and solve the equation. So, let's replace x with 0:
3(0) - 2y = -12
Simplifying, we get:
-2y = -12
Now, isolate y by dividing both sides of the equation by -2:
y = -12/-2
Simplifying further, we get:
y = 6
Therefore, the y-intercept is 6.
Thus, the solution to the equation 3x - 2y = -12 is (x, y) = (-4, 6).
Note: The solution you mentioned (2, -3) does not satisfy the given equation. Therefore, it is not the correct solution.