Find the x and y intercepts:

3x - 2y = -12

i know the anwser is (2 , -3) but how do i show the work that i found that anwser?

for the x intercept, put y=0 in the equation,solve for x. For the y intercept,do the reverse.

eh idk. i hate showing work so im just not going to do. i hate math i suck at it. im more biology, chemistry, science kid.^^

To find the x and y intercepts of a linear equation, you need to determine the points at which the line intersects the x-axis and the y-axis.

To find the x-intercept, we set y to zero and solve the equation. So, let's replace y with 0 in the given equation:

3x - 2(0) = -12

Simplifying, we get:

3x = -12

Now, isolate x by dividing both sides of the equation by 3:

x = -12/3

Simplifying further, we get:

x = -4

Therefore, the x-intercept is -4.

To find the y-intercept, you need to set x to zero and solve the equation. So, let's replace x with 0:

3(0) - 2y = -12

Simplifying, we get:

-2y = -12

Now, isolate y by dividing both sides of the equation by -2:

y = -12/-2

Simplifying further, we get:

y = 6

Therefore, the y-intercept is 6.

Thus, the solution to the equation 3x - 2y = -12 is (x, y) = (-4, 6).

Note: The solution you mentioned (2, -3) does not satisfy the given equation. Therefore, it is not the correct solution.