The toy car in figure 6-12 runs off the edge of a table that is 1.225-m high. The car lands 0.400m from the base of the table

a.How long did it take the car to fall?
b.How fast was the car going on the table?

To find the time it took for the car to fall off the table, we can use the equation d = 1/2 * g * t^2, where d is the vertical distance fallen, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time taken.

a. First, we need to find the time it took for the car to fall. The vertical distance fallen is equal to the height of the table, which is 1.225 m. Plugging this value into the equation, we have:

1.225 = 1/2 * 9.8 * t^2

To solve for t, we can rearrange the equation:

t^2 = (2 * 1.225) / 9.8
t^2 = 0.25
t = √0.25
t = 0.5 s

Therefore, it took the car 0.5 seconds to fall off the table.

b. Next, we can find the speed of the car when it lands 0.400 m from the base of the table. We can use the equation v = d / t, where v is the velocity, d is the horizontal distance traveled, and t is the time taken.

The horizontal distance traveled is given as 0.400 m. Plugging this value into the equation, along with the time taken as 0.5 s, we have:

v = 0.400 / 0.5
v = 0.8 m/s

Therefore, the car was traveling at a speed of 0.8 meters per second on the table.

time to fall 1.225m

h= 1/2 g t^2 find time

velocityhorizontal= distance/time