things do not go quite as planned. you invested $8000, part of it in stock that paid 12% annual interest. however, the rest of the money suffered a 55 loss. if the total annual income from both investments was $620, how much was invested at each rate?

Question

things do not go quite as planned. you invested $8000, part of it in stock that paid 12% annual interest. however, the rest of the money suffered a 55 loss. if the total annual income from both investments was $620, how much was invested at each rate?

Answer 1

Since the total profit was 620 which included the loss of 55, there must have been a profit of 675 from the first investment.

Assuming we are looking only at the one year, the question now becomes a simple interest problem where
P ?
I = 675
R = .12
T = 1
P = I/(RT)
= 675/.12 = 5625

so he invested $5625 at 12% ( the winner) and
$2375 in the losing investment.

Answer 2

what is 9000at 3%simple interest for 2and 1/2

Answer 3

To determine how much was invested at each rate, we can break down the problem into two parts.

Let's say you invested x amount of dollars in the stock that paid 12% interest. The remaining amount, which is (8000 - x), was invested in something that suffered a 55% loss.

Step 1: Calculate the income from the stock investment.
The income from the stock can be calculated using the formula: Principal * Rate of Interest. In this case, the principal is x dollars, and the interest rate is 12% or 0.12. Therefore, the income from the stock investment is 0.12x dollars.

Step 2: Calculate the loss from the other investment.
Since the remaining amount, (8000 - x) dollars, suffered a 55% loss, the amount left would be (1 - 0.55) times the initial amount. So the loss from the other investment is 0.45(8000 - x) dollars.

Step 3: Set up the equation for the total annual income.
The total annual income from both investments is given as $620. Therefore, we can write the equation:

0.12x + 0.45(8000 - x) = 620

Now, let's solve for x.

0.12x + 0.45(8000 - x) = 620
0.12x + 3600 - 0.45x = 620
0.12x - 0.45x = 620 - 3600
-0.33x = -2980
x = -2980 / -0.33
x = 9048.48

Since the question asks for an amount invested, we cannot have fractional amounts. Therefore, we round down the amount invested in the stock to $9000.

So, $9000 was invested in the stock that paid 12% interest, and the remaining amount, $8000 - $9000 = -$1000, was invested in something that suffered a loss. However, it is not possible to invest a negative amount, so there might be an error or discrepancy in the given information. Please double-check the given values to ensure accuracy.