AlgebraPlease checkI'm desperate
posted by JoniAnne
Posted by JoniAnne on Wednesday, October 20, 2010 at 11:50am.
Please check
Solve 3 > sqrt(3x)
3x >=o
x>=0/3
x>=0
square both sides and you have 3x < 3^2
3x,9
x<9/3
x<3
answer is 0<=x<3 correct or not?
3(cube) sqrt(25) = 3
cube both sides = 25x = 27
5x = 25
x = 5, correct?
Thank you

bobpursley
yes, on the 0=<x=<3
On the
3^3 sqrt (25x)=3
Hmmm. I don't know what you meant on the statement.
did you have
cbrt(25x)=3 ? if so
25x=27
5x=25
x=5 
JoniAnne
Yes, that's what I meant for the second onethank you for replying
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