posted by JoniAnne

Posted by JoniAnne on Wednesday, October 20, 2010 at 11:50am.

Solve 3 > sqrt(3x)
3x >=o
x>=0/3
x>=0

square both sides and you have 3x < 3^2
3x,9
x<9/3
x<3

answer is 0<=x<3 correct or not?

3(cube) sqrt(2-5) = 3
cube both sides = 2-5x = 27
-5x = 25
x = -5, correct?

Thank you

1. bobpursley

yes, on the 0=<x=<3

On the
3^3 sqrt (2-5x)=3

Hmmm. I don't know what you meant on the statement.

did you have
cbrt(2-5x)=3 ? if so
2-5x=27
-5x=25
x=-5

2. JoniAnne

Yes, that's what I meant for the second one-thank you for replying

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