Algebra-Please check-I'm desperate
posted by JoniAnne .
Posted by JoniAnne on Wednesday, October 20, 2010 at 11:50am.
Solve 3 > sqrt(3x)
square both sides and you have 3x < 3^2
answer is 0<=x<3 correct or not?
3(cube) sqrt(2-5) = 3
cube both sides = 2-5x = 27
-5x = 25
x = -5, correct?
yes, on the 0=<x=<3
3^3 sqrt (2-5x)=3
Hmmm. I don't know what you meant on the statement.
did you have
cbrt(2-5x)=3 ? if so
Yes, that's what I meant for the second one-thank you for replying