algebra

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assume that a jeweler needs 80 grams of an alloy that is 30% gold. He has avaliable one alloy that is 5% gold and another that is 85% gold; he will mix some of each If x equal the number of grams of the first alloy (so the number of grams of the second is 80-x), find x

  • algebra -

    solve
    .05x + .85(80-x) = .3(80)

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