solve the following pair of simultaneous equations.
2x-3y=13
3x+y=3
By elimination:
2x-3y=13 ...(1)
3x+y=3 ...(2)
Multiply (2) by 3 and add to (1)
2x-3y=13 ...(1)
9x+3y=9 ...(3)
Add(1) and (3)
11x = 22 ...(4)
Solve (4) to get
x=11
Substitute x=11 in (1) to solve for y.
I don't understand what you guys did here explain further
To solve this pair of simultaneous equations, we can use the method of substitution or elimination. I will explain the elimination method.
1. Start by multiplying both sides of the second equation by 3 to make the coefficient of y in both equations the same:
3(3x + y) = 3(3)
This simplifies to:
9x + 3y = 9
2. Now, we can add the two equations together to eliminate the variable y:
(2x - 3y) + (9x + 3y) = 13 + 9
This simplifies to:
11x = 22
3. Divide both sides of the equation by 11 to solve for x:
11x/11 = 22/11
This simplifies to:
x = 2
4. Now that we have found the value of x, substitute it back into either of the original equations to find the value of y. Let's use the first equation:
2(2) - 3y = 13
Simplify:
4 - 3y = 13
5. Move the constant term to the other side of the equation:
-3y = 13 - 4
-3y = 9
6. Divide both sides of the equation by -3 to solve for y:
-3y / -3 = 9 / -3
This simplifies to:
y = -3
Therefore, the solution to the pair of simultaneous equations is x = 2 and y = -3.
x=2, Substitute x=2 in (1) or (2). 2 is easier.
Thank you Jen.
yes, x=2.