How many carbon atoms are contained in 2.8g of C2H4?
6.022 x 10^23 is Avogadro's number, you use this to find the amount of particles in the concentration (moles)
To determine the number of carbon atoms in 2.8g of C2H4, we need to use the concept of molar mass and Avogadro's number.
First, let's calculate the molar mass of C2H4:
- The molar mass of carbon (C) is approximately 12.01 g/mol.
- The molar mass of hydrogen (H) is approximately 1.008 g/mol.
Since C2H4 contains two carbon atoms and four hydrogen atoms, the molar mass of C2H4 can be calculated as follows:
(2 * 12.01 g/mol) + (4 * 1.008 g/mol) = 28.05 g/mol.
Next, we can use the molar mass to determine the moles of C2H4 in 2.8g of the compound. We use the following formula:
Moles = Mass / Molar mass.
Moles = 2.8g / 28.05 g/mol = 0.0998 mol (rounded to four significant figures).
Since there are two carbon atoms in one mole of C2H4, the number of moles of carbon (C) atoms can be calculated as follows:
Number of moles of C atoms = Moles of C2H4 * 2 = 0.0998 mol * 2 = 0.1996 mol (rounded to four significant figures).
Finally, we can use Avogadro's number, which states that there are 6.022 × 10^23 atoms in one mole, to determine the number of carbon atoms:
Number of carbon atoms = Number of moles of C atoms * Avogadro's number
= 0.1996 mol * 6.022 × 10^23 atoms/mol
= 1.201 × 10^23 carbon atoms.
Therefore, there are approximately 1.201 × 10^23 carbon atoms in 2.8g of C2H4.
There are 2.8/molar mass C2H4 moles in 2.8 g C2H4.
There are 6.022 x 10^23 molecules in a mole of molecules. And you have ?? moles.