need some help, A ball with an initial angular velocity of 20.0 rads /s and a rotational inertia of 0.4kgm rolls uphill with an acceleration of -4.00 rad/s . Calculate the net torque acting on the ball. Calculate the angular displacement after 5.00 s.
To calculate the net torque acting on the ball, you can use the formula:
Net Torque = (Rotational Inertia) x (Angular Acceleration)
Given that the rotational inertia of the ball is 0.4 kgm and the angular acceleration is -4.00 rad/s, you can substitute these values into the formula:
Net Torque = 0.4 kgm x -4.00 rad/s
Net Torque = -1.6 Nm
Therefore, the net torque acting on the ball is -1.6 Nm.
To calculate the angular displacement after 5.00 s, you can use the formula:
Angular Displacement = (Initial Angular Velocity) x (Time) + (1/2) x (Angular Acceleration) x (Time^2)
Given that the initial angular velocity is 20.0 rads/s, the angular acceleration is -4.00 rad/s, and the time is 5.00 s, you can substitute these values into the formula:
Angular Displacement = 20.0 rads/s x 5.00 s + (1/2) x -4.00 rad/s x (5.00 s)^2
Angular Displacement = 100 rads - 50 rads
Angular Displacement = 50 rads
Therefore, the angular displacement after 5.00 s is 50 radians.