At a certain location, the Earth's magnetic field has a magnitude of 5.90E-5 T and points in a direction that is 71.6° below the horizontal. Calculate the magnitude of the magnetic flux through the top of a desk at this location that measures 132 cm by 83.3 cm.
B*A*cos71.6
Make sure the area is in sq. meters.
The flux will be in webers
Unless you show some work of your own on physics problems, I shll be reluctant to provide further assistance.
This is actually incorrect... The angle between the B field and the area is 90-71.6 degrees, or 75 degrees. B*A*COS angle.
To calculate the magnitude of the magnetic flux through the top of a desk, we can use the formula:
Φ = B*A*cos(θ)
where:
- Φ is the magnetic flux
- B is the magnetic field strength
- A is the area of the surface
- θ is the angle between the magnetic field and the surface normal (measured in degrees)
First, we need to calculate the area of the surface of the desk. The area can be found by multiplying the length and width of the desk:
A = length * width
Given that the length of the desk is 132 cm and the width is 83.3 cm, we can substitute these values into the formula:
A = 132 cm * 83.3 cm
Next, we need to convert the area to square meters, as the SI unit for magnetic field is Telsas (T) and the corresponding SI unit for area is square meters (m^2). To convert cm^2 to m^2, we divide the area by 10000:
A = (132 cm * 83.3 cm) / 10000 m^2
Now, we substitute this value for A into the equation for magnetic flux:
Φ = B * A * cos(θ)
Given that the magnetic field strength (B) is 5.90E-5 T and the angle (θ) is 71.6°, we can plug in these values:
Φ = (5.90E-5 T) * ((132 cm * 83.3 cm) / 10000 m^2) * cos(71.6°)
To evaluate this equation, you can use a scientific calculator or a calculator with trigonometric functions. By substituting the values and performing the calculations, you will find the magnitude of the magnetic flux through the top of the desk at the given location.