An object with a mass of 3.09x10^0 kg is subjected to a force of 8.8505x10^2 N directed at an angle of 1.6968x10^2 degrees from the x axis. A second force of 2.98725x10^3 N acting in the negative Y directions is also applied to the object. To two significant figures what is the net force acting in the Y direction (remember to include weight!)?
Note: Your answer is assumed to be reduced to the highest power possible.
Your Answer: x10
Answer
You have not said what direction is vertical. That would be the direction in which the weight force (30.28N) must be added. Once you know that, this is a routine vector addition problem with three vectors, and you only have to add components in the y direction.
I am left wondering why they are quoting forces to five significant figures and only asking for accuracy of two figures in the answer.
sides of a llgm are equal?
To find the net force acting in the Y direction, we need to consider two forces: the force applied at an angle from the x-axis and the force applied in the negative Y direction.
The force applied at an angle can be broken down into its x and y components using trigonometry. The x component is given by:
Fx = Force * cos(angle)
where Force is 8.8505x10^2 N and angle is 1.6968x10^2 degrees. We can calculate Fx:
Fx = 8.8505x10^2 N * cos(1.6968x10^2 degrees)
Next, the force applied in the negative Y direction is already in the Y direction, so we can simply consider it as the Y component.
Fy = -2.98725x10^3 N
Finally, we need to include the force due to the object's weight, which acts in the negative Y direction. The weight is given by the equation:
Weight = mass * gravity
where mass is 3.09x10^0 kg and gravity is the acceleration due to gravity (approximately 9.8 m/s^2). We can calculate the weight:
Weight = 3.09x10^0 kg * 9.8 m/s^2
Now, we can find the net force in the Y direction by summing all the Y components:
Net Force in Y direction = Fy + Weight
To reduce the answer to the highest power possible, you should express it in scientific notation by moving the decimal point until there is only one nonzero digit to the left of the decimal point.
I will calculate the net force in the Y direction for you.