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A 0.1943g iron ore sample was dissolved in hydrochloric acid and the iron was obtained as Fe 2+ (aq). The iron solution was titrated with Ce 4+ solution according to the balanced chemical reaction shown below.After calculation, it was found that 0.0237 g of iron from the ore reacted with the cerium solution.
Ce 4+(aq)+ Fe2+(aq) --> Ce3+ (aq)+ Fe3+ (aq)
Calculate the mass percent of iron in the original ore sample. Please round your answer to the tenths place

  • chemistry -

    %Fe = (0.0237/mass sample)*100 = ??

  • chemistry -

    12.2

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