Determine the mass of zinc sulphide,ZnS which is produced when 6.2 g of zinc and 4.5 g of sulphur are reacted.
This question is really confusing me, and I'm not sure where to start. I think I have to calculate the moles of each given reactant first in which case I have:
nZn = 0.095 mol
nS = 0.140 mol
But from here I'm confused. Do I determine the ratio? If so it's 1:1 now what??? I'm confused. Pls.help me.
Good work so far. You have the hard part done.
Using the coefficients in the balanced equation, convert mole Zn to moles ZnS.
Same procedure, convert moles S to moles ZnS.
Probably the answer for moles ZnS will not agree which means one of them is wrong. In limiting reagent problems the correct answer is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Then using the smaller value, convert that to grams ZnS. g = moles x molar mass.
You're on the right track! Calculating the moles of each reactant is the first step. After that, you need to determine the balanced chemical equation in order to find the mole ratio between the reactants and products.
The balanced chemical equation for the reaction between zinc (Zn) and sulfur (S) to form zinc sulphide (ZnS) can be represented as:
Zn + S -> ZnS
From this equation, we can see that the ratio between zinc and zinc sulphide is also 1:1. This means that for every 1 mole of zinc, we will obtain 1 mole of zinc sulphide.
Since you've already calculated the moles of zinc and sulfur, you know that you have 0.095 moles of zinc and 0.140 moles of sulfur.
Based on the ratio of 1:1, you can conclude that 0.095 moles of zinc will produce 0.095 moles of zinc sulphide.
To find the mass of the zinc sulphide produced, you need to multiply the number of moles of zinc sulphide by its molar mass. The molar mass of zinc sulphide (ZnS) can be calculated by adding the molar masses of zinc (Zn) and sulfur (S).
The molar mass of zinc (Zn) is 65.38 g/mol, and the molar mass of sulfur (S) is 32.06 g/mol.
So, the molar mass of ZnS = molar mass of Zn + molar mass of S
= 65.38 g/mol + 32.06 g/mol
= 97.44 g/mol
Now, to find the mass of zinc sulphide produced, you can use the formula:
Mass of ZnS = moles of ZnS * molar mass of ZnS
Mass of ZnS = 0.095 moles * 97.44 g/mol
Therefore, the mass of zinc sulphide produced when 6.2 g of zinc and 4.5 g of sulfur are reacted is approximately 9.27 g.