posted by Nick .
Use 2nd Fundamental Theorem of Calculus to find derivative of f(x) = integral of 2x^2 to x-5 of square root of Sin(t)dt.
I'm sorry, but the integrand
"2x^2 to x-5 of square root of Sin(t)dt."
does not make sense.
In general, the derivative of an indefinite integral of a function is the function itself.
Ok, so if I change it to 2x^2 to x-5 of square root of Sin(x)dx, does it make sense?
We haven't done any examples with an x in both the top and bottom of the integral sign.