Balance the following equations?
a) Fe(OH)2 + 2O2 + 3H2O �¨ Fe(OH)3
(b) 5Sr + 6H2O �¨ 7Sr(OH)2 + 8H2
(c) 9Al + 10Fe3O4 �¨ 11Al2O3 + 12Fe
(d) 13Pb(NO3)2 �¨ 14PbO + 15NO2 + 16O2
(e) 17O2 + 18N2H4 �¨ 19H2O2 + 20N2
(f) 21C4H10 + 22O2 �¨ 23CO2 + 24H2O
This is not phyics, whatever that is.
It is it physical science and the equations nedd to be balanced.... it just how the format is on the computer
To balance chemical equations, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's how you can balance each of the given equations:
a) Fe(OH)2 + 2O2 + 3H2O → Fe(OH)3
On the left side, there is 1 Fe, 2 O, and 3 H.
On the right side, there is 1 Fe, 3 O, and 3 H.
To balance the O atoms, multiply O2 by 3:
Fe(OH)2 + 6O2 + 3H2O → Fe(OH)3
Now the equation is balanced.
b) 5Sr + 6H2O → 7Sr(OH)2 + 8H2
On the left side, there are 5 Sr and 12 H.
On the right side, there are 7 Sr, 2 O, and 20 H.
To balance the H atoms, multiply H2O by 4 and H2 by 10:
5Sr + 24H2O → 7Sr(OH)2 + 8H2
Now the equation is balanced.
c) 9Al + 10Fe3O4 → 11Al2O3 + 12Fe
On the left side, there are 9 Al and 120 O.
On the right side, there are 22 Al and 36 O.
To balance the Al atoms, multiply Al2O3 by 2:
9Al + 10Fe3O4 → 22Al2O3 + 12Fe
Now the equation is balanced.
d) 13Pb(NO3)2 → 14PbO + 15NO2 + 16O2
On the left side, there are 13 Pb, 26 N, and 78 O.
On the right side, there are 14 Pb, 30 O, and 30 N.
To balance the Pb atoms, multiply PbO and NO2 by 13:
13Pb(NO3)2 → 14PbO + 15NO2 + 16O2
Now the equation is balanced.
e) 17O2 + 18N2H4 → 19H2O2 + 20N2
On the left side, there are 34 O and 36 H.
On the right side, there are 38 O and 38 H.
To balance both the O and H atoms, multiply H2O2 by 2:
17O2 + 18N2H4 → 38H2O2 + 20N2
Now the equation is balanced.
f) 21C4H10 + 22O2 → 23CO2 + 24H2O
On the left side, there are 84 C and 208 H.
On the right side, there are 23 C and 48 H.
To balance the C and H atoms, multiply C4H10 by 6:
21C4H10 + 22O2 → 23CO2 + 24H2O
Now the equation is balanced.
Remember, balancing chemical equations is a matter of trial and error. Keep adjusting coefficients until the number of atoms is balanced on both sides of the equation.