When calcium oxelate is treated with an acidic solution of potassium permanganate, the following reaction occurs:
CaC2O4(s) + MnO4-(aq) = Ca+2(aq) + CO2(g) + Mn+2(aq)
Balance the equation.
ca^2c2049s0+mn^2+co6-(aq^3)=4+(g)
You have to add some H+'s to make it all work.
5CaC2O4 + 2MnO4^- +6H^+ ==> 10CO2 + 8H2O + 2Mn^2+
I've left out the states since they make it more confusing when typing it out. I hope this helps!
To balance a chemical equation, we need to ensure that the same number of each type of atom is present on both sides of the equation. Here's how we can balance the given equation:
First, let's count the number of atoms on each side of the equation:
On the left side of the equation:
1Ca, 1C, and 4O atoms
On the right side of the equation:
1Ca, 1C, 1O, and 1Mn atoms
Based on these counts, we can see that the number of Ca and C atoms is already balanced since they have the same number on both sides. However, the number of O and Mn atoms is not balanced.
To balance the oxygen (O) atoms, we can add a coefficient (number in front of the chemical formula) of 2 in front of the CaCO3 on the right side:
CaC2O4(s) + MnO4-(aq) → Ca+2(aq) + 2CO2(g) + Mn+2(aq)
Now, we have 4 oxygen atoms on the right side (2CO2 x 2O), which matches the 4 oxygen atoms on the left side.
Finally, to balance the manganese (Mn) atoms, we can add a coefficient of 5/2 (or 2.5) in front of the KMnO4 on the left side:
5/2KMnO4 + CaC2O4(s) → Ca+2(aq) + 2CO2(g) + 5/2Mn+2(aq)
However, it is not ideal to have fractional coefficients. To eliminate the fractions, we can multiply the entire equation by 2 to obtain whole number coefficients:
5KMnO4 + 2CaC2O4(s) → 2Ca+2(aq) + 4CO2(g) + 5Mn+2(aq)
So, the balanced equation is:
5KMnO4 + 2CaC2O4(s) → 2Ca+2(aq) + 4CO2(g) + 5Mn+2(aq)