# physics

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A carton lies on a plane tilted at an angle theta 29 degrees to the horizontal, with a friction of uk .12.If the carton starts from rest 7.90 up the plane from its base, what will be the carton's speed when it reaches the bottom of the incline?

• physics -

The force of friction in the plane is
mu*mg*sinTheta
The gravity force down the plane is mgCosTheta

net force down the plane is
mgCosTheta-mu*mgSinTheta
the energy it gives to the box is that force times 7.9m
and that energy is equal to the KE at the bottom

(mgCosTheta-mu*mgSinTheta)*7.9=1/2 mv^2
solve for v.

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