physics

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A carton lies on a plane tilted at an angle theta 29 degrees to the horizontal, with a friction of uk .12.If the carton starts from rest 7.90 up the plane from its base, what will be the carton's speed when it reaches the bottom of the incline?

  • physics -

    The force of friction in the plane is
    mu*mg*sinTheta
    The gravity force down the plane is mgCosTheta

    net force down the plane is
    mgCosTheta-mu*mgSinTheta
    the energy it gives to the box is that force times 7.9m
    and that energy is equal to the KE at the bottom

    (mgCosTheta-mu*mgSinTheta)*7.9=1/2 mv^2
    solve for v.

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