physics
posted by Liz .
A horizontal force of 20 N acted on a 10 kg mass at rest. The force accelerated the mass over a rough surface so that the mass had a speed of 6.0 m/s after 5.0 seconds. How much friction was acting on the mass?

Net force=ma
(20Nfrictionforce)=10kg*6/5
solve for friction force
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